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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    A particle is travelling along a straight line OX. The distance \[x\] (in metre) of the particle from O at a time t is given by \[x=37+27t-{{t}^{3}},\]whem is time in seconds. The distance of the particle from O when it comes to rest is

    A)  81 m            

    B)  91m

    C)  101m           

    D)  111m

    Correct Answer: B

    Solution :

     Given, \[x=37+27t-{{t}^{3}}\] \[v=\frac{dx}{dt}=27-3{{t}^{2}}\] According to problem, \[v=0\Rightarrow 27-3{{t}^{2}}=0\] Here, t = 3 s \[x=37+27\times 3-{{(3)}^{2}}\] \[=91\,m\]


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