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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    Average distance of the Earth from the Sun is \[{{L}_{1}}.\] If one year of the Earth = D days, one year of another planet whose average distance from the Sun is \[{{L}_{2}}\] will be

    A)  \[D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{\frac{1}{2}}}days\]

    B)   \[D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{\frac{3}{2}}}days\]

    C)  \[D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{\frac{2}{3}}}days\]

    D)  \[D\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)days\]

    Correct Answer: B

    Solution :

     By Keplars law, \[{{T}^{2}}\propto {{R}^{3}}\] Hence      \[T=D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{3/2}}\]


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