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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    From the top of a tower, 80 m high from the ground, a stone is thrown in the horizontal direction with a velocity of \[8\,m{{s}^{-1}}.\]The stone reaches the ground after a time t and falls at a distance of d from the foot of the tower. Assuming \[=10m/{{s}^{2}},\] the time t and distance d are given respectively by

    A)  6 s, 64 m        

    B)  6 s, 48 m

    C)  4s, 32m          

    D)  4s, 16m

    Correct Answer: C

    Solution :

     Given, \[h=80\,m,v=8m{{s}^{-1}}\]and \[g=10\,m{{s}^{-2}}\] Here, \[h=\frac{1}{2}g{{t}^{2}}\] \[80=\frac{1}{2}\times 10\times {{t}^{2}}\] \[t=4s\] and \[x=vt=8\times 4=32\,m\]


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