2. Solved Papers
  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    A 100 mL \[0.1=(M)\] solution of ammonium acetate is diluted by adding 100 mL of water. The pH of the resulting solution will be (\[p{{K}_{a}}\] acetic acid is nearly equal to\[p{{K}_{b}}\]of\[N{{H}_{4}}OH\])

    A)  4.9              

    B)  5.0

    C)  7.0              

    D)  10.0

    Correct Answer: C

    Solution :

     Ammonium acetate is a salt of weak acid and weak base. When solutions of such salts diluted resulting pH of solution is calculated from following relationship \[pH=7+\frac{1}{2}p{{K}_{a}}-\frac{1}{2}p{{K}_{b}}\] \[\because \] \[p{{K}_{a}}\simeq p{{K}_{b}}\] (given) \[\therefore \] pH of diluted solution =7


You need to login to perform this action.
You will be redirected in 3 sec spinner