question_answer

The stability of \[M{{e}_{2}}C=C{{H}_{2}}\]is more than that of \[MeC{{H}_{2}}CH=C{{H}_{2}}\]due to

A)  inductive effect of the Me groups

B)  resonance effect of the Me groups

C)  hyperconjugative effect of the Me groups

D)  resonance as well as inductive effect of the Me groups

Correct Answer: C

Solution :

   has 6-hyper conjugate forms while   has 2-hyperconltjugate     forms.     Therefore,\[M{{e}_{2}}C=C{{H}_{2}}\]  is   more    stable    than\[MeC{{H}_{2}}CH=C{{H}_{2}}.\]