A) NaCI solution will show higher elevation of boiling point
B) Glucose solution will show higher elevation of boiling point
C) Both the solutions will show equal elevation of boiling point
D) The boiling point elevation will be shown by neither of the solutions
Correct Answer: A
Solution :
Elevation in boiling point, \[\Delta {{T}_{b}}=i\times {{K}_{b}}\times m\] Molality of NaCl solution \[=\frac{n}{W}\times 1000\] \[=\frac{\frac{58.5}{58.5}}{{{W}_{{{H}_{2}}O}}}\times 1000\] \[=\frac{1000}{{{W}_{{{H}_{2}}O}}}\] Molality of \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]solution \[=\frac{\frac{180}{180}\times 1000}{{{W}_{{{H}_{2}}}}O}\] \[=\frac{1000}{{{W}_{{{H}_{2}}O}}}\] Both the solutions have same molarity but the values for NaCI and glucose are 2 and 1 respectively. \[\therefore \] \[\Delta {{T}_{b(NaCl)}}=2\times \Delta {{T}_{b({{C}_{6}}{{H}_{12}}{{O}_{6}})}}\]
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