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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    The equivalent weight of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]in acidic medium is expressed in terms of its molecular  weight (M) as

    A)  M/3   

    B)  M/4 

    C)  M/6  

    D)  M/7

    Correct Answer: C

    Solution :

     In acidic medium, \[{{K}_{2}}\overset{+\,6}{\mathop{C{{r}_{2}}}}\,{{O}_{7}}\xrightarrow{{}}C{{r}^{3+}}\] Equivalent weight of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}=\frac{\text{Molecular}\,\text{weight}}{\text{Change}\,\text{in}\,\text{oxidation}\,\text{state}\,\text{of}\,\text{Cr}}\] \[=\frac{M}{2(6-3)}=\frac{M}{6}\]


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