WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    In a region, the intensity of an electric field is given by \[E=2i+3j+k\]in \[N{{C}^{-1}}.\]The electric flux through a surface \[S=10i\,{{m}^{2}}\]in the region  is

    A)  \[5\,N{{m}^{2}}{{C}^{-1}}\]

    B)  \[10\,N{{m}^{2}}{{C}^{-1}}\]

    C)  \[15\,N{{m}^{2}}{{C}^{-1}}\]

    D)  \[20\,N{{m}^{2}}{{C}^{-1}}\]

    Correct Answer: D

    Solution :

     Given \[E=(2i+3j+k)N{{C}^{-1}}\] and \[S=10\,i\,{{m}^{2}}\] We know that \[\text{o }\!\!|\!\!\text{ =}\,\text{E}\text{.S}\] \[\text{o }\!\!|\!\!\text{ =}\,\text{(2i}\,\text{+}\,\text{3j}\,\text{+}\,\text{k)}\text{.(10}\,\text{i)}\] \[\text{o }\!\!|\!\!\text{ =}\,\text{20}\,\text{N}{{\text{m}}^{2}}{{C}^{-1}}\]


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