2. Solved Papers
  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    The weight of oxalic acid that will be required to prepare a 1000 mL (N/20) solution is

    A)  126/100 g       

    B)  63/40 g

    C)  63/20 g         

    D)  126/20 g

    Correct Answer: C

    Solution :

     \[we=\frac{NEV}{1000}=\frac{1}{20}\times \frac{63\times 1000}{1000}=\frac{63}{20}g\]


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