A) \[\frac{3}{8}{{N}_{a}}{{K}_{B}}({{T}_{2}}-{{T}_{1}})\]
B) \[\frac{3}{2}{{N}_{a}}{{K}_{B}}({{T}_{2}}-{{T}_{1}})\]
C) \[\frac{3}{4}{{N}_{a}}{{K}_{B}}({{T}_{2}}-{{T}_{1}})\]
D) \[\frac{3}{4}{{N}_{a}}{{K}_{B}}\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)\]
Correct Answer: A
Solution :
We know that \[Q=\frac{F}{2}nR\,\Delta \Tau \] \[\therefore \] Amount of heat required, \[Q=\frac{3}{2}\times \frac{1}{4}\times {{K}_{B}}{{N}_{B}}\Delta \Tau \] \[Q=\frac{3}{2}\times \frac{1}{4}\times {{K}_{B}}{{N}_{B}}\Delta \Tau \]
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