WB JEE Medical WB JEE Medical Solved Paper-2013

  • question_answer
    A wave travelling in the positive \[x-\]direction having displacement along \[y-\]direction as 1 m, wavelength \[2\pi \,m\]and frequency of \[\frac{1}{\pi }Hz\]is represented by

    A)  \[y=\sin (x-2t)\]

    B)  \[y=\sin (2\pi x-2\pi t)\]

    C)  \[y=\sin (10\pi x-20\pi t)\]

    D)  \[y=\sin (2\pi x+2\pi t)\]

    Correct Answer: A

    Solution :

     Given a = 1 m As     \[y=a\,\sin (kx-\omega t)\] \[=\sin \left( \frac{2\pi }{2\pi }x-2\pi \times \frac{1}{\pi }t \right)\] \[=\sin (x-2t)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner