WB JEE Medical WB JEE Medical Solved Paper-2013

  • question_answer
    The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of \[10\,\Omega \] is

    A)  \[0.2\,\Omega \]

    B)  \[0.5\,\Omega \]

    C)  \[0.8\,\Omega \]

    D)  \[1.0\,\Omega \]

    Correct Answer: B

    Solution :

     \[l=\frac{E}{R+r}\] or \[E=l(R+r)\] \[2.1=0.2(10+r)\] \[10+r=\frac{2.1}{2}\times 10\] \[\therefore \] \[r=10.5-10=0.5\,\Omega \]


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