A) \[MeSiC{{l}_{3}}\]
B) \[M{{e}_{2}}SiC{{l}_{2}}\]
C) \[M{{e}_{3}}SiCl\]
D) \[PhSiC{{l}_{3}}\]
Correct Answer: C
Solution :
\[\text{M}{{\text{e}}_{\text{3}}}\text{SiCl}\]is not a monomer for a high molecular mass silicone polymer because it generates \[M{{e}_{3}}SiOH\]when subjected to hydrolysis which contains only one reacting site. Hence, the polymerisation reaction stops just after first step, \[Me-\underset{Me}{\overset{Me}{\mathop{\underset{|}{\overset{|}{\mathop{Si}}}\,}}}\,-OH+HO-\underset{Me}{\overset{Me}{\mathop{\underset{|}{\overset{|}{\mathop{Si}}}\,}}}\,-Me\xrightarrow[-{{H}_{2}}O]{}\]\[\underset{\text{Final}\,\text{product}\,\text{(dimer)}}{\mathop{Me-\underset{Me}{\overset{Me}{\mathop{\underset{|}{\overset{|}{\mathop{Si}}}\,}}}\,-O-\underset{Me}{\overset{Me}{\mathop{\underset{|}{\overset{|}{\mathop{Si}}}\,}}}\,-Me}}\,\]
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