A) \[C-1\]
B) \[C-2\]
C) \[C-3\]
D) \[C-4\]
Correct Answer: A
Solution :
Addition of a proton at \[{{C}^{1}}\]results in the formation of tropylium carbocation (an aromatic species with more stability due to delocalization of n electrons), thus, it is the most reactive site towards protonation. Addition of proton at any other carbon atom, interupt in the delocalisation of \[\pi \]electrons by disturbing planarity of molecules and hence, makes it less stable. Thus, these all are less reactive towards protonation.
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