A) \[2.16\times {{10}^{-23}}\]
B) \[3.21\times {{10}^{-22}}\]
C) \[3.21\times {{10}^{-24}}\]
D) \[1.26\times {{10}^{-23}}\]
Correct Answer: D
Solution :
Given, \[r=0.05\,nm=0.05\times {{10}^{-9}}m\] \[(\because \,1\,nm={{10}^{-9}}\,m)\] \[n={{10}^{16}}\]revolutions \[e=1.6\times {{10}^{-19}}C\] We know that The magnetic moment \[M=Ai\] \[M=\pi {{r}^{2}}\times ne\] \[M=3.14\times {{(0.05\times {{10}^{-9}})}^{2}}\times {{10}^{16}}\times 1.6\times {{10}^{-19}}\] \[M=0.1256\times {{10}^{-18}}\times {{10}^{16}}\times {{10}^{-19}}\] or \[M=1.26\times {{10}^{-23}}\,A{{m}^{2}}\]
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