A) \[\frac{\bar{A}+B}{(A+B)}.\bar{A}\]
B) \[\bar{A}\]
C) \[\overline{(\bar{A}+B)}.\bar{A}\]
D) \[\overline{(\bar{A}+B)}.A\]
Correct Answer: B
Solution :
By absorption laws \[Y=\bar{A}+\bar{A}.B\] or \[Y=(\bar{A}-B)+\bar{A}=\bar{A}.(B+1)=\bar{A}.1=\bar{A}\]
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