A) \[0.83\times {{10}^{3}}J\]
B) \[4.6\times {{10}^{3}}\,J\]
C) \[2.08\times {{10}^{3}}\,J\]
D) \[1.25\times {{10}^{3}}\,J\]
Correct Answer: D
Solution :
We know that\[\Delta U=n{{C}_{v}}\Delta T\] where \[\Delta T=({{T}_{2}}-{{T}_{1}})\] \[{{T}_{1}}=0{{\,}^{o}}C=273\,K\] \[{{T}_{2}}=100{{\,}^{o}}C=373\,K\] \[n=1\](monoatomic gas) \[R=8.32\,J\,mo{{l}^{-1}}{{K}^{-1}}=1\times \frac{3}{2}R\times (373-273)\] \[=1\times \frac{3}{2}\times 8.32\times 100=3\times 8.32\times 50\] \[\Rightarrow 1248\,kJ\]
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