A) \[\text{ }\!\![\!\!\text{ }Me\text{ }\!\!]\!\!\text{ }3{{s}^{2}},3{{p}^{6}},3{{d}^{9}},4{{s}^{2}}\]
B) \[\text{ }\!\![\!\!\text{ N}e\text{ }\!\!]\!\!\text{ }3{{s}^{2}},3{{p}^{6}},3{{d}^{10}},4{{s}^{1}}\]
C) \[\text{ }\!\![\!\!\text{ N}e\text{ }\!\!]\!\!\text{ }3{{s}^{2}},3{{p}^{6}},3{{d}^{3}},4{{s}^{2}},4{{p}^{6}}\]
D) \[\text{ }\!\![\!\!\text{ N}e\text{ }\!\!]\!\!\text{ }3{{s}^{2}},3{{p}^{6}},3{{d}^{5}},4{{s}^{2}},4{{p}^{4}}\]
Correct Answer: B
Solution :
Atomic number of Cu is 29. Thus, its electronic configuration can be written as \[C{{u}_{29}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},3{{d}^{10}},4{{s}^{1}}\] (Since, fully filled orbitals are more stable, so one electron from 4s orbital transfers into 3d orbital.) The electronic configuration of neon is \[N{{e}_{10}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}}\] Thus, using inert gas, the configuration of Cu can also be represented as \[C{{u}_{29}}=[Ne]3{{s}^{2}},3{{p}^{6}},3{{d}^{1}},4{{s}^{1}}\]
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