A) \[6.6\times {{10}^{-29}}cm\]
B) \[6.6\times {{10}^{-30}}cm\]
C) \[6.6\times {{10}^{-31}}cm\]
D) \[6.6\times {{10}^{-32}}cm\]
Correct Answer: C
Solution :
According to de-Broglie, wavelength, \[\lambda =\frac{h}{mv}\] Given, \[m=100\,g,v=100\,cm\,{{s}^{-1}}\] and \[h=6.6\times {{10}^{-34}}\,J-s\] \[=6.6\times {{10}^{-27}}\,erg-s\] On substituting values, we get \[\lambda =\frac{6.6\times {{10}^{-27}}}{100\times 100}=6.6\times {{10}^{-31}}\,cm\]
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