question_answer

The reagents to carry out the following conversion are

A)  \[HgS{{O}_{4}}/dil.{{H}_{2}}S{{O}_{4}}\]

B)  \[B{{H}_{3}};{{H}_{2}}{{O}_{2}}/NaOH\]

C)  \[Os{{O}_{4}};HI{{O}_{4}}\]

D)  \[NaN{{H}_{2}}/C{{H}_{3}}l;HgS{{O}_{4}}/dil.{{H}_{2}}S{{O}_{4}}\]

Correct Answer: D

Solution :

  (Here, Me means methyl group) Thus, the correct set of reagents is \[NaN{{H}_{2}}/C{{H}_{3}}I;HgS{{O}_{4}}/dil\,{{H}_{2}}S{{O}_{4}}.\]