A) the emission of an a-particle
B) the emission of a positron
C) capturing an orbital electron (K-electron capture)
D) emission of a p-particle
Correct Answer: B
Solution :
Emission of a positron results in the conversion of a proton into neutron, along with the release of neutrino. Thus, the number of protons decreases and of neutron increases, i.e., n/p ratio increases and the nuclei becomes stable. \[\underset{\text{Proton}}{\mathop{_{\text{1}}^{\text{1}}\text{H}}}\,\xrightarrow{{}}\underset{\text{Neutron}}{\mathop{_{\text{0}}^{\text{1}}\text{n}}}\,\text{+}\,\underset{\text{Positron}}{\mathop{_{\text{+1}}{{\text{e}}^{\text{0}}}}}\,\text{+}\,\text{v}\]
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