A) \[-1\]and\[+1\]
B) \[-1\] and\[+5\]
C) \[+\,1\]and \[+\,5\]
D) \[-1\] and \[+\,3\]
Correct Answer: B
Solution :
If \[\text{C}{{\text{l}}_{\text{2}}}\]is passed through hot aqueous NaOH, it results in the formation of sodium chloride and sodium chlorate as \[\underset{Hot}{\mathop{6NaOH}}\,+3C{{l}_{2}}\xrightarrow{{}}5NaCl+NaCl{{O}_{3}}+3{{H}_{2}}O\]In NaCI, let oxidation state of Cl be \[x.\] \[+1+x=0\]or \[x=-1\] In \[\text{NaCl}{{\text{O}}_{\text{3}}}\text{,}\]let oxidation state of Cl be y. \[+\,1+Y+(-2)\,3=0\] \[y-5=0\] \[\therefore \] \[Y=+\,5\] Thus, the obtained compounds have Cl in -1 and +5 oxidation states.
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