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WB JEE Medical WB JEE Medical Solved Paper-2014

  • question_answer
    The value of \[\Delta H\]for cooling 2 mole of an ideal monoatomic gas from \[225{{\,}^{o}}C\]to \[125{{\,}^{o}}C\]at  constant pressure will be [given \[{{C}_{p}}=\frac{5}{2}R\]]

    A)  250 R

    B)  \[-500\,R\]

    C)  \[500\,R\]

    D)  \[-250\,R\]

    Correct Answer: B

    Solution :

     \[\Delta \Eta =-n{{C}_{p}}\Delta =-2\times \frac{5}{2}R(225-125)\]\[=-5R(100)=-500R\]


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