A) 4 and 4
B) 5 and 5
C) 5 and 4
D) 4 and 3
Correct Answer: D
Solution :
Combination of four amino acid units gives a linear tetrapeptide, in which three peptide bonds are present. \[{{H}_{2}}N-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH+H-\overset{H}{\mathop{\overset{|}{\mathop{N}}\,}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-COOH\]\[+{{H}_{2}}N-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH+{{H}_{2}}N-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH\] \[{{H}_{2}}N-C{{H}_{2}}\underbrace{-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\overset{H}{\mathop{\overset{|}{\mathop{N}}\,}}\,-}_{\text{Peptide}\,\text{bond}}\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-\underbrace{-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\overset{H}{\mathop{\overset{|}{\mathop{N}}\,}}\,-}_{\text{Peptide}\,\text{bond}}C{{H}_{2}}\]\[\underbrace{-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{H}{\mathop{\underset{|}{\mathop{N}}\,}}\,}_{\begin{smallmatrix} \text{Peptide}\,\text{bond} \\ \text{(Tetrapeptide)} \end{smallmatrix}}-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH\]
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