A) \[4.25\text{ }g\text{ of }N{{H}_{3}}\]
B) \[8\,g\,\text{of}\,{{\text{O}}_{2}}\]
C) \[2g\,\text{of}\,{{H}_{2}}\]
D) \[4\text{ }g\,\text{of }He\]
Correct Answer: C
Solution :
Number of atoms \[\text{=}\frac{\text{mass}}{\text{molar}\,\text{mass}}\text{ }\!\!\times\!\!\text{ }{{\text{N}}_{\text{A}}}\]\[\text{ }\!\!\times\!\!\text{ }\] Number of atoms in 1 mole \[\therefore \]Number of atoms in \[4.25\text{ }g\text{ N}{{\text{H}}_{3}}\] \[=\frac{4.25}{17}\times {{N}_{A}}\times 4\]\[={{N}_{A}}\] Number of atoms in 8 g \[{{O}_{2}}=\frac{8}{32}\times {{N}_{A}}\times 2=\frac{{{N}_{A}}}{2}\] Number of atoms in 2 g \[{{H}_{2}}=\frac{2}{2}\times {{N}_{A}}\times 2=2{{N}_{A}}\] Number of atoms in 4 g \[He=\frac{4}{4}\times {{N}_{A}}\times 1={{N}_{A}}\] Thus, \[\text{2}\,\text{g}\,{{\text{H}}_{\text{2}}}\]contains the maximum number of atoms among the given.
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