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WB JEE Medical WB JEE Medical Solved Paper-2015

  • question_answer
    A train is moving with a uniform speed of 33 m/s and an observer is approaching the train with the same speed. If the train blows a whistle of frequency 1000 Hz and the velocity of sound is 333 m/s, then the apparent frequency of the sound that the observer hears is

    A)   1220 Hz

    B)  1099 Hz

    C)  1110 Hz

    D)  1200 Hz

    Correct Answer: A

    Solution :

     We have, Apparent frequency, \[v=\left( \frac{v+{{u}_{0}}}{v-{{u}_{s}}} \right){{v}_{0}}=\left( \frac{333+33}{333-33} \right)\times 1000\] \[=\frac{366}{300}\times 100=1220\,Hz\]


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