WB JEE Medical WB JEE Medical Solved Paper-2015

  • question_answer
    The atomic number of cerium (Ce) is 58. The correct electronic configuration of \[C{{e}^{3+}}\]ion is

    A)  \[[Xe]4{{f}^{1}}\]

    B)  \[[Kr]4{{f}^{1}}\]

    C)  \[[Xe]4{{f}^{13}}\]

    D)  \[[Kr]4{{d}^{1}}\]

    Correct Answer: A

    Solution :

     Atomic number of cerium \[=58\] Electronic configuration of \[\text{Ce}\] \[=[Xe]4{{f}^{2}},5{{d}^{0}},6{{s}^{2}}\] Electronic configuration of\[C{{e}^{3+}}\] \[=[Xe]4{{f}^{1}}\]


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