WB JEE Medical WB JEE Medical Solved Paper-2015

  • question_answer
    Sulphuryl chloride \[(S{{O}_{2}}C{{l}_{2}})\]reacts with white phosphorus \[({{P}_{4}})\] to give

    A) \[PC{{l}_{5}},S{{O}_{2}}\]          

    B)  \[OPC{{l}_{3}},SOC{{l}_{2}}\]

    C) \[PC{{l}_{5}},S{{O}_{2}},{{S}_{2}}C{{l}_{2}}\]    

    D)  \[OPC{{l}_{3}},S{{O}_{2}},{{S}_{2}}C{{l}_{2}}\]

    Correct Answer: A

    Solution :

     When sulphuryl chloride \[(S{{O}_{2}}C{{l}_{2}})\] reacts with white phosphorus \[({{P}_{4}}),\] it give phosphorus pentachloride \[(PC{{l}_{5}})\] and sulphur dioxide \[(S{{O}_{2}}).\] The reaction is as follows: \[{{P}_{4}}+10\,S{{O}_{2}}C{{l}_{2}}\xrightarrow{{}}4PC{{l}_{5}}+10S{{O}_{2}}\]


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