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WB JEE Medical WB JEE Medical Solved Paper-2015

  • question_answer
    In the following compound, the number of sp-hybridised carbons are \[C{{H}_{2}}=C=\underset{CN}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C\equiv CH\]

    A)  2        

    B)  3       

    C)  4      

    D)  5

    Correct Answer: C

    Solution :

    \[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{sp}{\mathop{C}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{sp}{\mathop{\underset{C\equiv N}{\mathop{\underset{|}{\mathop{\overset{s{{p}^{3}}}{\mathop{CH}}\,}}\,}}\,}}\,-\overset{sp}{\mathop{C}}\,\equiv \overset{sp}{\mathop{CH}}\,\] Thus, number of sp-hybridised \[C=4\]


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