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WB JEE Medical WB JEE Medical Solved Paper-2015

  • question_answer
    In aqueous alkaline solution, two electrons reduction of \[HO_{2}^{-}\]gives

    A) \[H{{O}^{-}}\]            

    B) \[{{H}_{2}}O\]

    C) \[{{O}_{2}}\]              

    D)  \[O_{2}^{-}\]

    Correct Answer: A

    Solution :

     In aqueous alkaline solution, two electron reduction of \[\text{HO}_{2}^{-}\]gives \[\bar{O}H.\]The reaction is as follows: \[{{H}_{2}}{{O}_{2}}{{H}^{+}}+HO_{2}^{-}\] \[HO_{2}^{-}+{{H}_{2}}O+2{{e}^{-}}3\bar{O}H\]


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