A) paramagnetic \[[Fe{{({{H}_{2}}O)}_{5}}(NO)]S{{O}_{4}}\]
B) diamagnetic \[[Fe{{({{H}_{2}}O)}_{5}}({{N}_{3}})]S{{O}_{4}}\]
C) paramagnetic \[[Fe{{({{H}_{2}}O)}_{5}}(N{{O}_{3}})]{{[S{{O}_{4}}]}_{2}}\]
D) diamagnetic \[[Fe{{({{H}_{2}}O)}_{4}}(S{{O}_{4}})]N{{O}_{3}}\]
Correct Answer: A
Solution :
Cold \[\text{FeS}{{\text{O}}_{\text{4}}}\]solution on absorption of NO develops brown colour due to the formation of \[[Fe{{({{H}_{2}}O)}_{5}}(NO)]S{{O}_{4}}.\] \[FeS{{O}_{4}}+NO+5{{H}_{2}}O\xrightarrow{{}}\] \[\underset{\text{Brown}\,\text{ring}\,\text{complex}}{\mathop{[Fe{{({{H}_{2}}O)}_{5}}(NO)]S{{O}_{4}}}}\,\] This complex has 3.89 BM magnetic moment shows that it has 3 unpaired electrons.
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