WB JEE Medical WB JEE Medical Solved Paper-2015

  • question_answer
    The units of surface tension and viscosity of liquids respectively are

    A)  \[kg\,{{m}^{-1}}{{s}^{-1}},N{{m}^{-1}}\]

    B)  \[kg\,{{s}^{-2}},kg\,{{m}^{-1}}{{s}^{-1}}\]

    C)  \[N{{m}^{-1}},kg\,{{m}^{-1}}{{s}^{-2}}\]

    D)  \[kg\,{{s}^{-1}},\,kg\,{{m}^{-2}}{{s}^{-1}}\]

    Correct Answer: B

    Solution :

     From the formula, Surface tension, \[(\gamma )\] \[=\frac{\Delta W}{\Delta A}=\frac{J}{{{m}^{2}}}=\frac{kg\,{{m}^{2}}{{s}^{-2}}}{{{m}^{2}}}=kg\,{{s}^{-2}}\] Form the formula, \[F=\eta .A.\frac{dV}{dx}\] or, \[\eta \](coefficient of viscosity) \[=\frac{F}{A.\frac{dV}{dx}}=\frac{H}{{{m}^{2}}.\frac{m{{s}^{-1}}}{m}}=N{{m}^{-2}}.s\] or \[kg\,m{{s}^{-2}}.{{m}^{-2}}.s=kg\,{{m}^{-1}}{{s}^{-1}}\]


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