A) ferric ferricyanide
B) ferrous ferricyanide
C) ferric ferrocyanide
D) ferrous ferrocyanide
Correct Answer: C
Solution :
To a part of sodium extract, \[\text{FeS}{{\text{O}}_{\text{4}}}\]solution is added and the contents are warmed. A few drops of \[\text{FeC}{{\text{l}}_{\text{3}}}\]solution are then added and resulting solution is acidified with cone. \[\text{HCl}\text{.}\]The appearance of bluish green or Prussian blue colouration confirms the presence of nitrogen. The reactions that occur during this test are as \[2NaCN\text{ }+\,FeS{{O}_{4}}\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+Fe{{(CN)}_{2}}\]\[Fe{{(CN)}_{2}}+4NaCN\xrightarrow{{}}\underset{\text{Sodium}\,\text{ferrocyanide}}{\mathop{N{{a}_{4}}[Fe{{(CN)}_{6}}]}}\,\] \[3\,N{{a}_{4}}[Fe{{(CN)}_{6}}]+4FeC{{l}_{3}}\xrightarrow{{}}\] \[\underset{\begin{smallmatrix} \text{Ferric}\,\text{ferrocyanide} \\ (Prussian\,blue) \end{smallmatrix}}{\mathop{F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}}}\,+12NaCl\]
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