A) Electron will be knocked out of the atom
B) Electron will go to any excited state of the atom
C) Electron will go only to first excited state of the atom
D) Electron will keep orbiting in the ground state of the atom
Correct Answer: D
Solution :
The energy of the photon \[E=\frac{hc}{\lambda }\] \[=\frac{4\times {{10}^{-15}}eVs\times 3\times {{10}^{8}}m/s}{300\times {{10}^{-9}}m}\] \[=\frac{4\times {{10}^{2}}}{300}eV=\frac{4}{3}eV=1.33\,eV\] The ionisation energy is 13.6 eV which is greater than energy of photon, so atom can not come into excited state and will remain in ground state.You need to login to perform this action.
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