A) \[\frac{W\tan \theta }{\mu }\]
B) \[\mu W\,\tan \theta \]
C) \[\mu W\sqrt{1+{{\tan }^{2}}\theta }\]
D) \[\mu W\sin \theta \]
Correct Answer: B
Solution :
Let weight of A is W. From the free body diagram, For equilibrium of the system, \[T\,\cos \theta =\mu N=\mu W\] ?(i) \[T\sin \theta =W\] ?(ii) where, T = tension in the thread lying between knot and the support. On divindg Eq. (ii) by Eq. (i). we get \[\frac{T\sin \theta }{T\cos \theta }=\frac{W}{\mu W}\] \[\Rightarrow \] \[\tan \theta =\frac{W}{\mu W}\Rightarrow \mu W\tan \theta \]You need to login to perform this action.
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