Answer:
\[\underset{{{s}_{1}}}{\mathop{AgCN}}\,\to
\underset{{{s}_{1}}}{\mathop{A{{g}^{+}}}}\,+\underset{{{s}_{1}}}{\mathop{C{{N}^{-}}}}\,\]
\[{{K}_{sp}}=s_{1}^{2}\]
\[{{s}_{1}}=\sqrt{{{K}_{sp}}}=\sqrt{6\times
{{10}^{-17}}}\]
\[=7.8\times
{{10}^{-9}}M\]
\[\underset{{{s}_{2}}}{\mathop{Ni{{(OH)}_{2}}}}\,\to
\underset{{{s}_{2}}}{\mathop{N{{i}^{2+}}}}\,+\underset{2{{s}_{2}}}{\mathop{2O{{H}^{-}}}}\,\]
\[{{K}_{sp}}=[N{{i}^{2+}}]{{[O{{H}^{-}}]}^{2}}\]
\[={{s}_{2}}{{(2{{s}_{2}})}^{2}}=4s_{2}^{3}\]
\[^{{{s}_{2}}={{\left( \frac{2\times {{10}^{-15}}}{4}
\right)}^{1/3}}}\]
\[=7.93\times {{10}^{-6}}M\]
Thus, \[Ni{{(OH)}_{2}}\]
is more soluble.
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