Answer:
\[\underset{s}{\mathop{{{A}_{x}}{{B}_{y}}}}\,\to
\underset{xs}{\mathop{x{{A}^{y+}}}}\,+\underset{ys}{\mathop{y{{B}^{x-}}}}\,\]
Solubility product \[{{K}_{sp}}={{[{{A}^{y+}}]}^{x}}{{[{{B}^{x-}}]}^{y}}\]
\[={{[xs]}^{x}}{{[ys]}^{y}}\]
\[={{x}^{x}}{{y}^{y}}{{x}^{x+y}}\]
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