Answer:
(i) \[C{{H}_{3}}-\underset{\underset{{{\,}^{2}}C{{H}_{2}}\overset{1}{\mathop{C}}\,{{H}_{3}}}{\mathop{|}}\,}{\mathop{\overset{3}{\mathop{C}}\,}}\,H-\overset{4}{\mathop{C}}\,{{H}_{2}}-\overset{5}{\mathop{C}}\,{{H}_{2}}-\overset{6}{\mathop{C}}\,{{H}_{3}}\]
The longest chain is of six
carbon atoms and not five. Therefore, the correct name of the compound is 3-methylhexane.
(ii) \[\overset{1}{\mathop{C{{H}_{3}}}}\,-\overset{2}{\mathop{C}}\,{{H}_{2}}-\underset{\underset{{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}}{\mathop{\text{
}\!\!|\!\!\text{ }}}\,}{\mathop{\overset{3}{\mathop{C}}\,}}\,H-\overset{4}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{\text{C}{{\text{H}}_{\text{3}}}}{\mathop{\text{
}\!\!|\!\!\text{
}}}\,}{\overset{5}{\mathop{CH}}}\,-\overset{6}{\mathop{C{{H}_{2}}}}\,-\overset{7}{\mathop{C}}\,{{H}_{3}}\]
In case there are different (ethyl and methyl) alkyl substituents
at equivalent positions then numbering is to be started in alphabetical order.
Since 'e' comes before m, hence, the correct name is 3-ethyl-5-methylheptane.
You need to login to perform this action.
You will be redirected in
3 sec