Answer:
10 volume solution of \[{{H}_{2}}{{O}_{2}}\] means
that 1L of this \[{{H}_{2}}{{O}_{2}}\] solution will give 10L of oxygen at STP
\[\underset{\begin{smallmatrix}
234g \\
68g
\end{smallmatrix}}{\mathop{2{{H}_{2}}{{O}_{2}}(l)}}\,\to
\underset{22.7\text{ L at STP}}{\mathop{{{O}_{2}}(g)+{{H}_{2}}O(l)}}\,\]
on
the basis of above equation 22.7 L of \[{{O}_{2}}\] is produced from \[66g\,\,{{H}_{2}}{{O}_{2}}\]
at STP 10 L of \[{{O}_{2}}\] at STP is produced from
\[\frac{66\,\,\,10}{22.7}g=22.9\,g\]
\[30\,g\,{{H}_{2}}{{O}_{2}}\]
Therefore,
strength of \[{{H}_{2}}{{O}_{2}}\] in 10 volume \[{{H}_{2}}{{O}_{2}}\] solution
\[=30\,\,g/L\,\,=3%\,\,{{H}_{2}}{{O}_{2}}\]solution.
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