question_answer 1)

Show that             = (1 + a2 + b2)3.  

Answer:

Let       Operate                   Taking 1 + a2 + b2 as common from C1 and C2, we get             Expand along C1, we get                   = (1 + a2 + b2)2             = (1 + a2 + b2)2 [1 ? a2 ? b2 + 2a2 + 2b2]       = (1 + a2 + b2)2 (1 + a2 + b2)       = (1 + a2 + b2)3