Answer:
Circumference of the circular sheet = 154 m \[\Rightarrow \] Radius of the circular sheet (r) \[=\frac{154\times 7}{2\times 22}=\frac{49}{2}\text{m}\] \[\therefore \] Area of the sheet \[=\pi {{r}^{2}}=\frac{22}{7}{{\left( \frac{49}{2} \right)}^{2}}{{\text{m}}^{\text{2}}}\] \[=\frac{22}{7}\times \frac{49}{2}\times \frac{49}{2}\times {{\text{m}}^{\text{2}}}=1886.\text{5 }{{\text{m}}^{\text{2}}}\]
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