Answer:
Molecular mass of \[^{235}U{{F}_{6}}=235+6\times
19=349\]
Molecular mass of \[^{238}U{{F}_{6}}=238\,+6\times
19=352\]
\[\therefore \] \[\,\frac{{{r}_{1}}{{(}^{235}}U{{F}_{6}})}{{{r}_{2}}{{(}^{238}}U{{F}_{6}})}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\,=\sqrt{\frac{352}{349}}\,=1\cdot
004\]
Thus, \[r{{(}^{235}}U{{F}_{6}}):r\,{{(}^{238}}U{{F}_{6}})=1\cdot
004:1\].
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