A) Alkane
B) Alkene
C) Alkyne
D) All
Correct Answer: B
Solution :
\[\underset{\underset{Br\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{Br\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,}}\,}{\mathop{C{{H}_{2}}}}\,+Zn\to \underset{\text{Alkene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+B{{r}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
