A) \[C{{H}_{3}}CH=CHC{{H}_{3}}\] predominates
B) \[C{{H}_{2}}=CHC{{H}_{2}}C{{H}_{3}}\] predominates
C) Both are formed in equal amounts
D) The amount of production depends on the nature of catalyst
Correct Answer: A
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\underset{475\,K}{\mathop{\xrightarrow{{{H}_{2}}S{{O}_{4}}}}}\,\]\[\underset{\text{More symmetrical}\,(\text{major}\,\text{product)}}{\mathop{C{{H}_{3}}-CH=CH-C{{H}_{3}}}}\,\] \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\underset{475\,K}{\mathop{\xrightarrow{{{H}_{2}}S{{O}_{4}}}}}\,\]\[\underset{\begin{smallmatrix} \text{Less symmetrical or } \\ \text{unsymmetrical} \\ \text{(minor product)} \end{smallmatrix}}{\mathop{C{{H}_{2}}=CH-C{{H}_{2}}-C{{H}_{3}}}}\,\] It is based on Saytzeff?s rule. According to this more symmetrical or more alkylated alkene predominates.
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