JEE Main & Advanced Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank Alkyne

  • question_answer
    When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative [CBSE PMT 1989; MP PMT 1993]

    A) \[{{C}_{2}}{{H}_{6}}\]

    B) \[{{C}_{2}}{{H}_{4}}\]

    C) \[{{C}_{2}}{{H}_{2}}\]

    D) \[{{C}_{6}}{{H}_{6}}\]

    Correct Answer: C

    Solution :

               \[2N{{H}_{4}}OH+C{{u}_{2}}C{{l}_{2}}\to 2CuOH+2N{{H}_{4}}Cl\]                    \[N{{H}_{4}}OH+CuOH\to \underset{\begin{smallmatrix}  \text{Diammine copper} \\  \text{ }\left( I \right)\text{ hydroxide} \end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{2}}]OH}}\,\]                    \[2[Cu{{(N{{H}_{3}})}_{2}}]\,OH+HC\equiv CH\to \] \[\underset{\text{copper acetylide Red ppt}\text{.}}{\mathop{Cu-C\equiv C-Cu}}\,+4N{{H}_{3}}+2{{H}_{2}}O\]


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