A) \[{{60}^{o}}\]
B) \[{{120}^{o}}\]
C) \[{{150}^{o}}\]
D) \[{{135}^{o}}\]
Correct Answer: C
Solution :
Gradient of the line which passes through (1, 0) and \[(-2,\,\sqrt{3})\] is \[m=\frac{\sqrt{3}-0}{-2-1}=-\frac{1}{\sqrt{3}}\] Þ \[\theta ={{\tan }^{-1}}\left( -\frac{1}{\sqrt{3}} \right)={{150}^{o}}\].
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