JEE Main & Advanced Mathematics Sequence & Series Question Bank Arithmetic Progression

  • question_answer
    \[{{n}^{th}}\] term of the series  \[3.8+6.11+\] \[9.14+12.17+.....\]will be

    A) \[3n(3n+5)\]

    B) \[3n(n+5)\]

    C) \[n(3n+5)\]

    D) \[n(n+5)\]

    Correct Answer: A

    Solution :

    Given series  \[3\,.\,8+6\,.\,11+9\,.\,14+12\ .\,17+.....\] First factors are 3, 6, 9, 12 whose \[{{n}^{th}}\]term is \[3n\] and second factors are 8, 11, 14, 17 \[{{t}_{n}}=[8+(n-1)3]=(3n+5)\] Hence \[{{n}^{th}}\]term of given series\[=3n(3n+5)\].


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