A) \[0.2\] moles
B) \[0.1\] mole
C) \[2\] moles
D) \[1\] mole
Correct Answer: B
Solution :
Gram molecular weight of\[AgN{{O}_{3}}\] \[=(1\times 108+1\times 14+3\times 16)\] \[=108+14+48=170\,\,g\] Number of moles of\[AgN{{O}_{3}}\] \[\frac{17\,\,g}{170\,\,g}=\frac{1}{10}=0.1\]moleYou need to login to perform this action.
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