A) \[CoF_{6}^{3-}\] and \[NiCl_{4}^{2-}\]
B) \[TiF_{6}^{2-}\] and \[CoF_{6}^{3-}\]
C) \[C{{u}_{2}}C{{l}_{2}}\] and \[NiCl_{4}^{2-}\]
D) \[TiF_{6}^{2-}\] and \[C{{u}_{2}}C{{l}_{2}}\]
Correct Answer: D
Solution :
\[TiF_{6}^{2-}\] and \[C{{u}_{2}}C{{l}_{2}}\] due to absence of unpaired electrons.
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