A) \[^{5}{{C}_{3}}\times {{\,}^{4}}{{C}_{2}}\]
B) \[\frac{^{5}{{C}_{3}}\times {{\,}^{4}}{{C}_{2}}}{5}\]
C) \[^{5}{{C}_{3}}\times {{\,}^{4}}{{C}_{3}}\]
D) \[{{(}^{5}}{{C}_{3}}\times {{\,}^{4}}{{C}_{2}})\,(5)\,!\]
Correct Answer: D
Solution :
The letters can be select in \[^{5}{{C}_{3}}{{\times }^{4}}{{C}_{2}}\] ways. Therefore the number of arrangements are \[{{(}^{5}}{{C}_{3}}{{\times }^{4}}{{C}_{2}})\,\,5\ !\].
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